22t=-9.8t^2+22

Solution for 22t=-9.8t^2+22 equation:

22t=-9.8t^2+22

We move all terms to the left:

22t-(-9.8t^2+22)=0

We get rid of parentheses

9.8t^2+22t-22=0

a = 9.8; b = 22; c = -22;
Δ = b2-4ac
Δ = 222-4·9.8·(-22)
Δ = 1346.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-\sqrt{1346.4}}{2*9.8}=\frac{-22-\sqrt{1346.4}}{19.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+\sqrt{1346.4}}{2*9.8}=\frac{-22+\sqrt{1346.4}}{19.6}
$